Team:Imperial College London/Modelling/Protein Display/Detailed Description
From 2010.igem.org
m |
m |
||
Line 147: | Line 147: | ||
<h2>6. Localised concentrations</h2> | <h2>6. Localised concentrations</h2> | ||
- | It was realised that for | + | It was realised that, for our choice of control volume, the system would be unlikely to perform well due to the high concentration levels of TEV or Schistosoma proteases that would be required. Hence, it was deduced that localised concentrations will play an important role in this model. |
<br/> | <br/> | ||
- | It was arbitrarily chosen that 20% to 50% of AIPs will bind to receptors rather than diffuse away. There | + | It was arbitrarily chosen that 20% to 50% of AIPs will bind to receptors rather than diffuse away. There are several arguments that would suggest this kind of percentage: |
- | <ul><li> | + | <ul><li> AIPs being very close to the cell surface will have an equal probability of heading back towards the bacterium as diffusing away from it (since the cell is a lot bigger than the AIPs).</li> |
- | <li>It is likely that there will be some chemical interactions between | + | <li>It is likely that there will be some chemical interactions between AIPs and the bacterium that could be attracting the AIPs to the host bacterium (e.g. electrostatic attraction could be possible).</li> |
</ul> | </ul> | ||
- | The percentage coefficient scales the AIP concentrations at the very end - after the ODE equations have been solved | + | The percentage coefficient scales the AIP concentrations at the very end - after the ODE equations have been solved. |
<h2>7. Protein production</h2> | <h2>7. Protein production</h2> | ||
<ul> | <ul> | ||
- | <li> | + | <li>This paper mentions that each cell displays 2.4×10<sup>5</sup> peptides. <a href="http://onlinelibrary.wiley.com/doi/10.1111/j.1574-6968.2000.tb09188.x/pdf">[2]</a></li> |
<li>2.4×10<sup>5</sup> molecules = 2.4×10<sup>5</sup>/6.02×10<sup>23</sup> mol = 0.398671×10<sup>-18</sup> mol</li> | <li>2.4×10<sup>5</sup> molecules = 2.4×10<sup>5</sup>/6.02×10<sup>23</sup> mol = 0.398671×10<sup>-18</sup> mol</li> | ||
<li>Volume of B.sub cell wall: 0.32×10<sup>-15</sup>m<sup>3</sup></li> | <li>Volume of B.sub cell wall: 0.32×10<sup>-15</sup>m<sup>3</sup></li> |
Revision as of 17:02, 26 October 2010
Modelling | Overview | Detection Model | Signaling Model | Fast Response Model | Interactions |
A major part of the project consisted of modelling each module. This enabled us to decide which ideas we should implement. Look at the Fast Response page for a great example of how modelling has made a major impact on our design! |
Objectives | Description | Results | Constants | MATLAB Code |
Detailed Description | ||
This model consists of 5 parts that had to be developed:
1. Elements of the system
2. Interactions between elementsApart from the proteins being expressed from genes, there was only one more chemical reaction identified in this part of the system. This is the cleavage of proteins, which is an enzymatic reaction:
This enzymatic reaction can be rewritten as ordinary differential equations (ODEs), which is of similar form as the 1-step amplification model. However, most of the constants and initial concentrations are different. 3. Threshold concentration of AIPThe optimal peptide concentration required to activate ComD is 10 ng/ml [1]. This is the threshold value for ComD activation. However, the minimum concentration of peptide to give a detectable activation is 0.5ng/ml.The threshold for the minimal activation of the receptor is cth=4.4658×10-9 mol/L. Click on the button below to uncover the calculations. Converting 10 ng/ml to 4.4658×10-9 mol/L
4. Cell Wall VolumeThe volume of the cell wall was necessary to be calculated for calculation of concentrations in enzymatic reaction.Volume of B. subtilis is 2.79μm3 and the thickness of cell wall is 35nm [5]. In order to approximate the cell wall volume assume that B. subtilis is a sphere - not a rod. Calculate the outer radius from the total volume: 0.874μm. Now subtract the thickness of cell wall from outer radius to determine inner radius of the sphere: 0.839μm. The volume of cell wall equals to the difference between outer volume and the inner volume (calculated from inner radius): cell wall volume=0.32×10-15m3 5. Control volume selectionNote that product of the enzymatic reaction, AIP, is allowed to diffuse outside the cell. Hence, it is important to take into account the cell boundaries. It is worth considering whether diffusion or fluid movements will play a significant role.Initially, we defined a control volume assuming that bacteria would grow in close colonies on the plate. We realized that our initial choice of control volume was not accurate, since our bacteria are meant to be used in suspension so we had to reconsider this issue.
Initial Choice of Control Volume
Control volume initial choice
The control volume: The inner boundary is determined by the bacterial cell (proteins after being displayed and cleaved cannot diffuse back into bacterium). The outer boundary is more time scale dependent. We have assumed that after mass cleavage of the display-proteins by TEV, many of these AIPs will bind to the receptors quite quickly (eg. 8 seconds). Our volume is determined by the distance that AIPs could travel outwards by diffusion within that short time. In this way, we are sure that the concentration of AIPs outside our control volume after a given time is approximately 0. This approach is not very accurate and can lead us to false negative conclusions (as in reality there will be a concentration gradient, with highest concentration on the cell wall).
Using CFU to estimate the spacing between cells CFU stands for Colony-forming unit. It is a measure of bacterial numbers. For liquids, CFU is measured per ml. We already have data of CFU/ml from the Imperial iGEM 2008 team, so we could use this data to estimate the number of cells in a given volume using a spectrometer at 600nm wavelength. The graph below is taken from the Imperial iGEM 2008 Wiki page [4].
Side length of cubic Control volume is y = 1.26×10-4 dm = 1.26×10-5 m. Choice of Control Volume allows simplifications
6. Localised concentrationsIt was realised that, for our choice of control volume, the system would be unlikely to perform well due to the high concentration levels of TEV or Schistosoma proteases that would be required. Hence, it was deduced that localised concentrations will play an important role in this model.It was arbitrarily chosen that 20% to 50% of AIPs will bind to receptors rather than diffuse away. There are several arguments that would suggest this kind of percentage:
7. Protein production
Hence, we can deduce that the final concentration that the protein expression will tend to is: c = 1.24×10-3 mol/dm3 = cfinal. Therefore, we can model the protein production by transcription and translation and adjust the production constants so that the concentration will tend towards cfinal. The degradation rate was kept constant (same as used in output amplification module), and the production rate was adjusted match the final concentration to be achieved. Using a similar model to the simple production of Dioxygenase for the Output Amplification Model (Model preA), we obtain the following graph:
References
|