Team:Cambridge/Tools/Lighting

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'''Efficiency = (X*T<sub>night</sub>) / (471.13*60A*T<sub>day</sub>)'''
'''Efficiency = (X*T<sub>night</sub>) / (471.13*60A*T<sub>day</sub>)'''
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where '''T<sub>day</sub>''' and '''T<sub>night</sub>''' are the hours of daylight and night time respectively. If we choose the least bright street lamp ('''X=210''') and hypothesise a projected area of '''A=30m<sup>2</sup>''', and a '''day:night ratio 14:10'''  then we find that the efficiency must be roughly '''0.02%'''. This means that 0.02% of the total energy hitting the tree must be converted eventually into light output, a potentially achievable target.
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where '''T<sub>day</sub>''' and '''T<sub>night</sub>''' are the hours of daylight and night time respectively. If we choose the least bright street lamp ('''X=210''') and hypothesise a projected area of '''A=30m<sup>2</sup>''', and a '''day:night ratio 14:10'''  then we find that the efficiency must be roughly '''0.02%'''. This means that 0.02% of the total energy which the tree absorbs in photosynthesis must be converted eventually into light output, a potentially achievable target.
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Revision as of 15:54, 27 October 2010