Team:HokkaidoU Japan/Test2

From 2010.igem.org

(Difference between revisions)
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a
a
<math>\begin{eqnarray}
<math>\begin{eqnarray}
-
a_0=\frac{1}{\pi}\left[\int_0^{\pi} a \sin kt \cdot dt + \int_{\pi}^{2\pi} (-a) \sin kt \cdot dt\right]=0
+
\int_{}^{}
\end{eqnarray} </math>
\end{eqnarray} </math>

Revision as of 10:17, 23 July 2010

a <math>\begin{eqnarray} \int_{}^{}

\end{eqnarray} </math>